Answer
no triangle.
Work Step by Step
1. Use the Law of Sines, we have $\frac{2}{sinA}=\frac{1}{sin100^\circ}=\frac{b}{sinB}$
2. $A=sin^{-1}(\frac{2sin100^\circ}{1})=sin^{-1}(1.97)$ no triangle.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 7 - Applications of Trigonometric Functions - Section 7.2 The Law of Sines - 7.2 Assess Your Understanding - Page 552: 33
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