Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 7 - Applications of Trigonometric Functions - Section 7.2 The Law of Sines - 7.2 Assess Your Understanding - Page 552: 32

Answer

no triangle.

Work Step by Step

1. Use the Law of Sines, we have $\frac{7}{sinB}=\frac{3}{sin70^\circ}=\frac{c}{sinC}$ 2. $B=sin^{-1}(\frac{7sin70^\circ}{3})=sin^{-1}(2.19)$ no triangle.
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