Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.6 Double-angle and Half-angle Formulas - 6.6 Assess Your Understanding - Page 518: 22

Answer

$ \sqrt 2-1$

Work Step by Step

$tan(\frac{9\pi}{8})=tan\frac{1}{2}(\frac{9\pi}{4})=\frac{1-cos\frac{9\pi}{4}}{sin\frac{9\pi}{4}}=\frac{1-\sqrt 2/2}{\sqrt 2/2}=\sqrt 2-1$
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