Answer
$ \frac{\sqrt 3}{2}$
Work Step by Step
$sin(sin^{-1}\frac{1}{2}+cos^{-1}0)=sin(\frac{\pi}{6}+\frac{\pi}{2})=cos(\frac{\pi}{6})=\frac{\sqrt 3}{2}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.5 Sum and Difference Formulas - 6.5 Assess Your Understanding - Page 509: 73
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