Answer
$4$, $2$, $-\frac{2}{\pi}$.
See graph.
Work Step by Step
1. Given $y=4sin(\pi x+2)-5=4sin[\pi(x+\frac{2}{\pi})]-5$, we can find the amplitude $|A|=4$, period $p=\frac{2\pi}{\pi}=2$, and phase shift $-\frac{2}{\pi}$.
2. See graph.
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