Answer
$4$, $\pi$, $\frac{\pi}{2}$.
See graph.
Work Step by Step
1. Given $y=4sin(2x-\pi)=4sin2(x-\frac{\pi}{2})$, we can find the amplitude $|A|=4$, period $p=\frac{2\pi}{2}=\pi$, and phase shift $\frac{\pi}{2}$.
2. See graph.
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