Answer
$\frac{4\sqrt 3-6}{\pi}$.
Work Step by Step
1. Given $f(x)=sec(x)$, we have $f(0)=sec(0)=1$ and $f(\frac{\pi}{6})=sec(\frac{\pi}{6})=\frac{2\sqrt 3}{3}$,
2. The rate of change required is given by $\frac{f(\frac{\pi}{6})-f(0)}{\frac{\pi}{6}-0}=\frac{\frac{2\sqrt 3}{3}-1}{\frac{\pi}{6}}=\frac{4\sqrt 3-6}{\pi}$.