Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.5 Graphs of the Tangent, Cotangent, Cosecant, and Secant Functions - 5.5 Assess Your Understanding - Page 442: 41

Answer

$\frac{2\sqrt 3}{\pi}$.

Work Step by Step

1. Given $f(x)=tan(x)$, we have $f(0)=tan(0)=0$ and $f(\frac{\pi}{6})=tan(\frac{\pi}{6})=\frac{\sqrt 3}{3}$, 2. The rate of change required is given by $\frac{f(\frac{\pi}{6})-f(0)}{\frac{\pi}{6}-0}=\frac{\frac{\sqrt 3}{3}}{\frac{\pi}{6}}=\frac{2\sqrt 3}{\pi}$.
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