Answer
$\frac{2\sqrt 3}{\pi}$.
Work Step by Step
1. Given $f(x)=tan(x)$, we have $f(0)=tan(0)=0$ and $f(\frac{\pi}{6})=tan(\frac{\pi}{6})=\frac{\sqrt 3}{3}$,
2. The rate of change required is given by $\frac{f(\frac{\pi}{6})-f(0)}{\frac{\pi}{6}-0}=\frac{\frac{\sqrt 3}{3}}{\frac{\pi}{6}}=\frac{2\sqrt 3}{\pi}$.