Answer
$ \frac{1}{15}\ sec$, $120\ A$.
See graph.
Work Step by Step
1. Given $I(t)=120sin(30\pi t), t\ge0$, we can determine the period $p=\frac{2\pi}{30\pi}=\frac{1}{15}\ sec$, amplitude $|A|=120\ A$.
2. See graph.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Section 5.4 Graphs of the Sine and Cosine Functions* - 5.4 Assess Your Understanding - Page 434: 88
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