Answer
$\frac{1}{30}\ sec$, $220\ V$.
See graph.
Work Step by Step
1. Given $I(t)=220sin(60\pi t), t\ge0$, we can determine the period $p=\frac{2\pi}{60\pi}=\frac{1}{30}\ sec$, amplitude $|A|=220\ V$.
2. See graph.
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