Answer
$1,\frac{\pi}{2}$.
Work Step by Step
For $y=sin(x)$, we can find, within $[0,2\pi]$, a maximum value of $y=1$ at $x=\frac{\pi}{2}$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Section 5.4 Graphs of the Sine and Cosine Functions* - 5.4 Assess Your Understanding - Page 431: 3
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