## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$\text{Amplitude} = 2$ $\text{Period}=T= 2\pi$
Recall: For $y=A\sin{({\omega}x)}$, we have: $\text{Amplitude}=|A|$ and $\text{Period}=T=\frac{2\pi}{\omega}$ In $y=2\sin x$ we have $A=2$ and $\omega=1$, so Amplitude= $|A|=2$ Period $T=\frac{2\pi}{\omega}=\frac{2\pi}{1}=2\pi$