Answer
$Range, R \approx 19541.95 \ m $
$Height, H \approx 2278.14 \ m $
Work Step by Step
We compute the range and height using the given formulas as follows:
Plug in $30^\circ$ for $\theta$ and $500$ for $v_o$ to obtain:
$Range, R =\dfrac{v_0^2 \sin{(2\theta)}}{g}=\dfrac{(500)^2\sin{(2 \times 25^\circ)}}{9.8} \approx 19541.95 \ m $
$Height, H =\dfrac{v_0^2\sin^2{(\theta)}}{2g}=\dfrac{(500)^2\sin^2{(25^\circ)}}{2 \times 9.8} \approx 2278.14 \ m $
