Answer
$Range, R \approx 1988.32 \ m $
$Height \approx 286.99 \ m $
Work Step by Step
We compute the range and height using the given formulas as follows:
$Range, R=\dfrac{v_0^2\sin{(2\theta)}}{g}=\dfrac{150^2 \sin{(2 \times \dfrac{\pi}{6})}}{9.8}=\dfrac{(150)^2 \times \dfrac{\sqrt3}{2}}{9.8} \approx 1988.32 \ m $
$Height =\dfrac{v_0^2\sin^2{(\theta)}}{2g}=\dfrac{(150) ^2 \times \sin^2{(\dfrac{\pi}{6})}}{9.8}=\dfrac{(150)^2 \times (\dfrac{1}{2})^2}{9.8}\approx 286.99 \ m $
