Answer
$-2$
Work Step by Step
We will use the Trigonometric Identity
$\sin^2 \theta+\cos^2 \theta =1$
We evaluate the given expression to obtain:
$\sin (14^{\circ})^2+\cos (14^{\circ})^2 -3$
or, $=1-3$
or, $=-2$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Cumulative Review - Page 460: 9
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