Answer
$x^2+(y+2)^2=16$
Work Step by Step
The standard equation for a circle with radius $r$ and center $(h,k)$ is given by:
$(x−h)^2+(y−k)^2=r^2$
We have: Center $(h,k)=(0,-2)$
$(x−0)^2+[y−(−2)]^2=4^2$
Thus, $x^2+(y+2)^2=16$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Cumulative Review - Page 460: 3
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