Answer
$\frac{7\sqrt {53}}{53}$.
Work Step by Step
Given point $(2,7)$ in quadrant I, we have $x=2, y=7$, thus $r=\sqrt {(2)^2+(7)^2}=\sqrt {53}$ and $sin\theta=\frac{y}{r}=\frac{7\sqrt {53}}{53}$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Chapter Test - Page 460: 22
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