Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.8 Exponential Growth and Decay Models; Newton's Law; Logistic Growth and Decay Models - 4.8 Assess Your Understanding - Page 356: 4

Answer

(a) $-0.087$ or $-8.7\%$. (b) $ 45.7\ g$ (c) $ 4.1$ days. (d) $ 8.0$ days.

Work Step by Step

Given $A(t)=A_0e^{-0.087t}=100e^{-0.087t}$, we have: (a) The decay rate of iodine-131 is $-0.087$ or $-8.7\%$. (b) $A(9)=100e^{-0.087(9)}\approx45.7\ g$ (c) $A(t)=100e^{-0.087(t)}=70\Longrightarrow t=\frac{ln(0.7)}{-0.087}\approx4.1$ days. (d) $A(t)=100e^{-0.087(t)}=100/2 \Longrightarrow t=\frac{ln(1/2)}{-0.087}\approx8.0$ days.
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