Answer
(a) $ 1000$ bacteria.
(b) $0.01$ or $1\%$.
(c) $ 1041$ bacteria.
(d) see below.
(e) $ 69.3$ hours.
Work Step by Step
Given $N(t)=1000e^{0.01t}$, we have:
(a) $N(0)=1000e^{0}=1000$ bacteria.
(b) The growth rate of the bacteria is $0.01$ or $1\%$.
(c) $N(4)=1000e^{0.01(4)}\approx1041$ bacteria.
(d) $N(t)=1000e^{0.01t}=?$ (the book did not give a number).
(e) $N(t)=1000e^{0.01t}=2(1000) \Longrightarrow t=\frac{ln(2)}{0.01}\approx69.3$ hours.
