Answer
$C e^{-2x}$.
Work Step by Step
Given $ln(y)=-2x+ln(C)$, we have $y=e^{-2x+lnC}=C e^{-2x}$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 4 - Exponential and Logarithmic Functions - Section 4.5 Properties of Logarithms - 4.5 Assess Your Understanding - Page 332: 92
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