Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.5 Properties of Logarithms - 4.5 Assess Your Understanding - Page 332: 67

Answer

$ log_a(\frac{25x^6}{\sqrt {2x+3}})$

Work Step by Step

$2log_a(5x^3)-\frac{1}{2}log_a(2x+3)=log_a(25x^6)-log_a\sqrt {2x+3}=log_a(\frac{25x^6}{\sqrt {2x+3}})$
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