#### Answer

$\log_a{1.6}=2$

#### Work Step by Step

RECALL:
$b^x=y \longrightarrow \log_b{y}=x$
Use the rule above to obtain:
$a^2=1.6 \longrightarrow \log_a{1.6}=2$

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Published by
Pearson

ISBN 10:
0-32193-104-1

ISBN 13:
978-0-32193-104-7

$\log_a{1.6}=2$

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