Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.2 One-to-One Functions; Inverse Functions - 4.2 Assess Your Understanding - Page 293: 82

Answer

The inverse of the function $f(x)$ decreases on $(f(0),f(5))$.

Work Step by Step

If a function $f(x)$ is one-to-one, then for all $y=f(x)$, there is only one $x$. This means that the domain of the function $f(x)$ becomes the range of the inverse function and the range of the inverse function $f^{-1}(x)$ becomes the domain of the inverse function. We are told that $f(x)$ is decreasing on $(0,5)$. Thus we know that it will pass the horizontal line test and will be a one-to-one function with an inverse. We also know that the inverse, $f^{-1}(x)$, is decreasing on $(f(0),f(5))$.
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