Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.2 One-to-One Functions; Inverse Functions - 4.2 Assess Your Understanding - Page 293: 76

Answer

$-5$

Work Step by Step

By the definition of an inverse one-to-one function, if $g(x)=y$, then we have $g^{-1} (y)=x$. Since $g(x)$ is a one-to-one function, then for each $x$ there must be a unique $g(x)$ and all the $g(x)$ values will be distinct. Therefore, when $g(-5)=3 $, then its inverse can be expressed as: $g^{-1} (3) =-5$ In other words, when finding the inverse of a function, the $x$ and $y$ values get switched.
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