Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.2 One-to-One Functions; Inverse Functions - 4.2 Assess Your Understanding - Page 292: 60

Answer

$f^{-1}(x)=\frac{4}{x}-2$ See graph.

Work Step by Step

Step 1. $f(x)=\frac{4}{x+2} \Longrightarrow y=\frac{4}{x+2} \Longrightarrow x=\frac{4}{y+2} \Longrightarrow y=\frac{4}{x}-2 \Longrightarrow f^{-1}(x)=\frac{4}{x}-2$ Step 2. Check $f(f^{-1}(x))=\frac{4}{(\frac{4}{x}-2)+2}=x$ and $f^{-1}(f(x))=\frac{4}{\frac{4}{x+2}}-2=x$ Step 3. See graph.
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