Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Cumulative Review - Page 373: 15

Answer

(a) $-1$. (b) $ \{x|x\gt-1\}$. (a) $25$.

Work Step by Step

Given $f(x)=log_3(x+2)$, we have: (a) $f(x)=0 \Longrightarrow log_3(x+2)=0 \Longrightarrow x+2=1, x=-1$. (b) $f(x)\gt0 \Longrightarrow x+2\gt1 \Longrightarrow \{x|x\gt-1\}$. (a) $f(x)=3 \Longrightarrow log_3(x+2)=3 \Longrightarrow x+2=3^3, x=25$.
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