Answer
$2$
Work Step by Step
1. $log_3(x+1)+log_3(2x-3)=log_99 \Longrightarrow log_3[(x+1)(2x-3)]=1 \Longrightarrow 2x^2-x-3=3^1 \Longrightarrow 2x^2-x-6=0 \Longrightarrow (2x+3)(x-2)=0 \Longrightarrow x=-\frac{3}{2}, 2$.
2. Check $x=2$ fit(s).
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 4 - Exponential and Logarithmic Functions - Cumulative Review - Page 373: 14
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