Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 2 - Linear and Quadratic Functions - Section 2.7 Complex Zeros of a Quadratic Function* - 2.7 Assess Your Understanding - Page 178: 36

Answer

(a) domain $[-3,3]$, range $[-2,2]$. (b) $(-3,0),(0,0),(3,0)$ (c) origin. (d) function.

Work Step by Step

Based on the given graph, we can find: (a) domain $[-3,3]$, range $[-2,2]$. (b) intercepts $(-3,0),(0,0),(3,0)$ (c) We can identify that the curve is symmetric with respect to the origin. (d) We can determine the relation is a function as it will pass a vertical line test.
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