Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 2 - Linear and Quadratic Functions - Section 2.7 Complex Zeros of a Quadratic Function* - 2.7 Assess Your Understanding - Page 178: 32

Answer

$\pm3,\pm3i$

Work Step by Step

$G(y)=y^4-81=(y^2+9)(y^2-9)$. Let $G(y)=0$, we get $y=\pm3,\pm3i$
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