Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 2 - Linear and Quadratic Functions - Section 2.6 Building Quadratic Models from Verbal Descriptions and from Data - 2.6 Assess Your Understanding - Page 174: 35

Answer

$\frac{-4\pm\sqrt {31}}{5}$

Work Step by Step

Let $f(x)=0$, we have $5x^2+8x-3=0 \longrightarrow x=\frac{-8\pm\sqrt {64+4(5)(3)}}{2(5)}=\frac{-4\pm\sqrt {31}}{5}$
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