Answer
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In general, we have $y^2\ge0$ for all real numbers. For $(x-2)^2$ it will be positive except when $x=2$ which given a zero. Thus $(x-2)^2\gt0$ will be true for all real numbers of $x$ except $x=2$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 2 - Linear and Quadratic Functions - Section 2.5 Inequalities Involving Quadratic Functions - 2.5 Assess Your Understanding - Page 164: 38
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