Answer
$x=4$
Work Step by Step
We need to simplify the inequality $(x-4)^2\leq 0$
We know that the square of a real number is non-negative, so the left side of the equation is never negative and we can write: $(x-4)^2=0$.
The next step is to evaluate this equation to obtain:
$$(x-4)^2=0\\
\sqrt{(x-4)^2}=\pm \sqrt{0}\\
x=4$$
Therefore, the solution to the inequality $(x-4)^2\leq 0$ is: $x=4$