## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

The point of intersection is $(-8, 180)$.
We want to find when $f(x) = g(x)$, so we set the two expressions equal to one another and solve: $3(x^2 - 4) = 3x^2 + 2x + 4$ Use the distributive property: $3x^2 - 12 = 3x^2 + 2x + 4$ Move all terms to the left side of the equation: $-2x - 16 = 0$ Factor out common terms: $-2(x + 8) = 0$ Divide both sides by $-2$: $x + 8 = 0$ Subtract $8$ from each side of the equation: $x = -8$ We can now plug this value into either $f(x)$ or $g(x)$ to find the points of intersection of the two graphs. Let's use $f(x)$: $f(x) = 3[(-8)^2 - 4]$ Evaluate exponents first: $f(x) = 3(64 - 4)$ Simplify what is in parentheses: $f(x) = 3(60)$ Multiply to simplify: $f(x) = 180$ The point of intersection is $(-8, 180)$.