Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 2 - Linear and Quadratic Functions - Section 2.3 Quadratic Functions and Their Zeros - 2.3 Assess Your Understanding - Page 147: 94

Answer

$-\frac{5}{2},\frac{1}{5}$, $(-\frac{5}{2},\frac{25}{2})$, $(\frac{1}{5},\frac{22}{5})$.

Work Step by Step

Step 1. Let $f(x)=g(x)$ to get $10x^2+20x=-3x+5 \longrightarrow 10x^2+23x-5=0 \longrightarrow (2x+5)(5x-1)=0 \longrightarrow x=-\frac{5}{2},\frac{1}{5}$, Step 2. For $x=-\frac{5}{2}$, we have $g(-\frac{5}{2})=-3(-\frac{5}{2})+5=\frac{25}{2}$ or intersect $(-\frac{5}{2},\frac{25}{2})$, Step 3. For $x=\frac{1}{5}$, we have $g(\frac{1}{5})=-3(\frac{1}{5})+5=\frac{22}{5}$ or intersect $(\frac{1}{5},\frac{22}{5})$.
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