Answer
$\frac{2\pm\sqrt {6}}{2}$
Work Step by Step
Let $f(x)=0$, we have $-2x^2+4x+1=0 \Longrightarrow x=\frac{-4\pm\sqrt {16-4(-2)}}{2(-2)}=\frac{2\pm\sqrt {6}}{2}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 2 - Linear and Quadratic Functions - Chapter Test - Page 187: 4
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