Answer
$-\frac{4}{3}, 2$
Work Step by Step
Let $f(x)=0$, we have $3x^2-2x-8=0 \Longrightarrow (3x+4)(x-2)=0$, thus $x=-\frac{4}{3}, 2$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 2 - Linear and Quadratic Functions - Chapter Test - Page 187: 3
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