Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Section 13.1 Finding Limits Using Tables and Graphs - 13.1 Assess Your Understanding - Page 896: 48

$\dfrac{13}{28}\approx 0.46$

As we can see from the attached graph, as $x$ gets closer and closer to $3$ from the left and the right, the value of the function (the $y$-value) gets closer and closer to $\frac{13}{28}$. Thus the limit is $\displaystyle \lim_{x\to3}\frac{x^3-3x^2+4x-12}{x^4-3x^3+x-3}=\frac{13}{28}\approx 0.46$