Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Section 13.1 Finding Limits Using Tables and Graphs - 13.1 Assess Your Understanding - Page 896: 48


$\dfrac{13}{28}\approx 0.46$

Work Step by Step

As we can see from the attached graph, as $x$ gets closer and closer to $3$ from the left and the right, the value of the function (the $y$-value) gets closer and closer to $\frac{13}{28}$. Thus the limit is $\displaystyle \lim_{x\to3}\frac{x^3-3x^2+4x-12}{x^4-3x^3+x-3}=\frac{13}{28}\approx 0.46$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.