Answer
slope$=16$
See graph.
Work Step by Step
1. Find the derivative of $f(x)=x^3+x^2$ as $f'(x)=3x^2+2x$
2. Find the slope of the tangent line $m=f'(2)=16$
3. Find the line equation $y-12=16(x-2)$ or $y=16x-20$
4. See graph.
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