Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Chapter Review - Review Exercises - Page 926: 26

Answer

The function is discontinuous at $x=0$.

Work Step by Step

We can see that the graph has a gap at $x=0$. The left and right limits do not match each other and the right limit does not match the function value at $x=0$. Therefore, the function is said to be discontinuous at $x=0$.
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