Answer
(a) $0.68$
(b) $ 0.58$
(c) $ 0.32$
Work Step by Step
(a) Given $P_1=0.6, P_2=0.1, P(1\cap 2)=0.02$, we have $P(1\cup2)=0.6+0.1-0.02=0.68$
(b) $P(1\ not\ 2)=P_1-P(1 \cap 2)=0.6-0.02=0.58$
(c) $P(not\ 1,2)=1-P(1\cup2)=1-0.68=0.32$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 12 - Counting and Probability - Chapter Review - Review Exercises - Page 889: 26
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