Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 12 - Counting and Probability - Chapter Review - Review Exercises - Page 889: 25

Answer

$0.2,0.26$

Work Step by Step

We know that probability$=\frac{\text{number of favourable outcomes}}{\text{number of all outcomes}}.$ We have $100$ numbers in total. There are $\frac{100}{5}=20$ numbers that are divisible by $5$. Thus: $P=\frac{20}{100}=0.2$ The primes: $\{2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97\}$. Thus there are $25+1=26$ numbers that are primes or $1$. Thus, our probability is: $P=\frac{26}{100}=0.26$
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