Answer
$(x+1)^2=4(y-2)$
Work Step by Step
1. Based on the given conditions, we have the vertex $(-1,2)$, parabola opens to the right, general form $(x+1)^2=4p(y-2)$
2. With $p=1$ we have the equation $(x+1)^2=4(y-2)$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 11 - Sequences; Induction; the Binomial Theorem - Cumulative Review - Page 860: 8
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