Answer
$15.8^\circ$
Work Step by Step
1. Based on the given conditions, we can find the vertical drop as $h=5300-4100=1200\ ft$.
2. With the length $L=4420\ ft$, we have
$sin\theta=\frac{1200}{4420}=\frac{60}{221}$
$\theta=sin^{-1}(\frac{60}{221})\approx15.8^\circ$