Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 10 - Systems of Equations and Inequalities - Section 10.6 Systems of Nonlinear Equations - 10.6 Assess Your Understanding - Page 797: 103

Answer

$ y=-\frac{2}{5}x-3$

Work Step by Step

With the given slope and point, use the point-slope form, we have $y+7=-\frac{2}{5}(x-10)$ or $y+7=-\frac{2}{5}x+4$, thus $y=-\frac{2}{5}x-3$
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