Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 10 - Systems of Equations and Inequalities - Section 10.5 Partial Fraction Decomposition - 10.5 Assess Your Understanding - Page 788: 58

Answer

$(\frac{\sqrt 2}{2},\frac{\sqrt 2}{2})$ See graph.

Work Step by Step

1. Given polar coordinates $(-1,\frac{5\pi}{4})$, use transformation formulas, we have $x=(-1)cos(\frac{5\pi}{4})=\frac{\sqrt 2}{2}$ and $y=(-1)sin(\frac{5\pi}{4})=\frac{\sqrt 2}{2}$, thus the rectangular coordinates $(\frac{\sqrt 2}{2},\frac{\sqrt 2}{2})$ 2. See graph.
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