Answer
False
Work Step by Step
The cube function, $f(x)=\sqrt [3] x$ is odd. However, the function is increasing, not decreasing, on the interval $(-\infty,\infty)$.
Consider the function values at these two points:
$f(1)=\sqrt [3] 1=1$
while
$f(27)=\sqrt[3]{27}=3$
This means that as $x$ increases, $y$ increases as well.
So, the statement is False.
