## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$a) f(0)=-4 \\ b) f(1)=-2 \\ c) f(2)=0 \\ d) f(3) =25$
In order to find $f(0), f(1), f(2), f(3)$, we will plug in the $x$ values into the piece of the graph whose interval includes that $x$ value. $a) f(0)=(2)(0)-4=-4 \\ b) f(1)=(2)(1)-4=-2 \\ c) f(2)=(2)(2)-4=0 \\ d) f(3) =(3)^3-2 =25$