Answer
See graph, local maximum $f(0)=5$, local minimum $f(2)=1$,
increasing on $(-1,0), (2,3)$, decreasing on $(0,2)$.
Work Step by Step
Step 1. See graph for $f(x)=x^3-3x^2+5$,
Step 2. We can find a local maximum $f(0)=5$, a local minimum $f(2)=1$,
Step 3. the function is increasing on $(-1,0), (2,3)$, decreasing on $(0,2)$.
