Answer
$\text{Even }$
Work Step by Step
Recall:
a) A function is said to be odd, when every number $x$ in its domain, the number $-x$ is also in the domain such that $g(-x)=-g(x)$
b) A function is said to be even, when every number $x$ in its domain, the number $-x$ is also in the domain such that $g(-x)=g(x)$
Replace in the given function $-x$ with $x$ to evaluate $g(-x)$.
$g(-x)=\dfrac{1}{(-x)^2} \\g(-x)=\dfrac{1}{x^2} \\g(-x)=g(x)$
Therefore, the function $g(x)$ is even.
