Answer
$\frac{x-1}{x+1}, x\ne0$
Work Step by Step
$(f/g)(x)=f(x)/g(x)=\frac{1/x}{g(x)}=\frac{x+1}{x^2-x}$, thus $g(x)=\frac{x^2-x}{x(x+1)}=\frac{x-1}{x+1}, x\ne0$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 1 - Functions and Their Graphs - Section 1.1 Functions - 1.1 Assess Your Understanding - Page 54: 74
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